The radius of a wheel is 30.0 cm and that of its axle is 6.0cm. Calculate the effort required to lift a load of 120.0N using this machine. Assuming 100% efficiency
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Correct Answer: Option C
Explanation:
V.R = \(\frac{R}{r} = \frac{30}{6} = 5\)
\(\gamma = \frac{M.A}{V.R} \times \frac{100}{1} \)
M.A = \(\frac{100 \times 5}{100} = 5\)
Effort = \(\frac{L}{M.A} = \frac{120}{5}\)
= 24N
V.R = \(\frac{R}{r} = \frac{30}{6} = 5\)
\(\gamma = \frac{M.A}{V.R} \times \frac{100}{1} \)
M.A = \(\frac{100 \times 5}{100} = 5\)
Effort = \(\frac{L}{M.A} = \frac{120}{5}\)
= 24N