A body is pulled over a distance of 500m by a force of 20N. If the power developed is o.4 kW, calculate the time interval during which the force is applied
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Correct Answer: Option C
Explanation:
t = \(\frac{fs}{p} = \frac{20 \times 500}{0.4 \times 1000} = 25s\)
t = \(\frac{fs}{p} = \frac{20 \times 500}{0.4 \times 1000} = 25s\)