An object is placed 20.0cm in front of a converging lens of focal length 15.0cm. Calculate its image distance
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Correct Answer: Option D
Explanation:
\(\frac{1}{v} = \frac{1}{f} - \frac{1}{U}\)
\(\frac{1}{15} - \frac{1}{20} = 60cm\)
\(\frac{1}{v} = \frac{1}{f} - \frac{1}{U}\)
\(\frac{1}{15} - \frac{1}{20} = 60cm\)