Using the circuit diagram above. Calculate the total charge in the circuit
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Correct Answer: Option D
Explanation:
C - \(C_1 + C_2 = 2 + 6 = \mu F\)
\(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{2}\)
C = \(\frac{8}{5 \mu F}\)
Q = CV
= \(\frac{8}{5} \times 10 = 16\mu C\)
C - \(C_1 + C_2 = 2 + 6 = \mu F\)
\(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{2}\)
C = \(\frac{8}{5 \mu F}\)
Q = CV
= \(\frac{8}{5} \times 10 = 16\mu C\)