A stone projected horizontally from the top of a tower with a speed of 4 ms\(^{-1}\) lands on the level ground at a horizontal distance of 25 m from the foot of the tower. Calculate the height of the tower. = 10 ms\(^{-2}\)]
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Correct Answer: Option n
Explanation:
R = U\(\sqrt{\frac{2h}{g}}\)
h = \(\frac{R^2g}{2u^2}\)
= \(\frac{25^2 \times 10}{2 \times 4^2}\)
= 195.3m
R = U\(\sqrt{\frac{2h}{g}}\)
h = \(\frac{R^2g}{2u^2}\)
= \(\frac{25^2 \times 10}{2 \times 4^2}\)
= 195.3m