The uncertainty in determining the duration during which an electron remains in a particular energy level before returning to the ground state is 2.0 x 10\(^{-9}\)s. Calculate the uncertainty in determining its energy at that level. (\(\frac{h}{2 \pi}\) = h = 1.054 x 10\(^{-34}\)Js)
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Correct Answer: Option n
Explanation:
\(\Delta E \geq \frac{h}{2 \pi} \times \frac{1}{\Delta t}\)
\(\geq 1.054 \times 10^{-37} \times \frac{1}{2 \times 10^{-9}}\)
\(\geq 5.27 \times 10^{-28}\)J
\(\Delta E \geq \frac{h}{2 \pi} \times \frac{1}{\Delta t}\)
\(\geq 1.054 \times 10^{-37} \times \frac{1}{2 \times 10^{-9}}\)
\(\geq 5.27 \times 10^{-28}\)J