A ray of light is incident on an air-glass boundary at an angle \(\theta\). If the angle between the partially reflected ray and the refracted ray is 90°, calculate \(\theta\), given that the refractive index of glass is 1.50.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option n
Explanation:
n = \(\frac{sin i}{sin r}\)
1.5 = \(\frac{sin \theta}{sin(190 - \theta)} = \frac{sin \theta}{cos theta} = \tan \theta\)
Hence, 0 = tan\(^{-1}\) 1.5 = 56.31\(^o\)
n = \(\frac{sin i}{sin r}\)
1.5 = \(\frac{sin \theta}{sin(190 - \theta)} = \frac{sin \theta}{cos theta} = \tan \theta\)
Hence, 0 = tan\(^{-1}\) 1.5 = 56.31\(^o\)