A body of mass 2kg is released from rest on a plane inclined at an angle of 60° to the horizontal. Calculate the acceleration of the body down the plane.[g = 10ms\(^{-2}\)]
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
a = g sin \(\theta\)
= 10 sin 60
= 8.7 ms\(^{-2}\)
a = g sin \(\theta\)
= 10 sin 60
= 8.7 ms\(^{-2}\)