A car starts from rest and covers a distance of 40m in 10s. Calculate the magnitude of its acceleration
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
S = ut + \(\frac{1}{2} at^2\)
40 = 0 x 10 + \(\frac{1}{2}\) x a x 102
50a = 40
a = \(\frac{40}{50}\)
= 0.8ms-2
S = ut + \(\frac{1}{2} at^2\)
40 = 0 x 10 + \(\frac{1}{2}\) x a x 102
50a = 40
a = \(\frac{40}{50}\)
= 0.8ms-2