A car traveling at 30ms\(^{-1}\) overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. [1 hp = 0.75 kW]
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Correct Answer: Option C
Explanation:
P = FV = \(\frac{100 \times 30}{1000} = 3 kW\)
\(\frac{3}{0.75} = 4hp\)
P = FV = \(\frac{100 \times 30}{1000} = 3 kW\)
\(\frac{3}{0.75} = 4hp\)