an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the observer from the cliff. [speed of sound in air = 330ms-1]
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Correct Answer: Option B
Explanation:
S = \(\frac{vt}{2} = \frac{330 \times 1.26}{2} = 207.9\)
S = \(\frac{vt}{2} = \frac{330 \times 1.26}{2} = 207.9\)