A body of mass 1000kg is released from a height of 10m above the ground. Determine its kinetic energy just before it strikes the ground .[g = 10ms-2]
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Correct Answer: Option D
Explanation:
Ke = mgh
Ke = Pe
\(\frac{1}{2}\)MV2 = mgh
Ke = 1000 x 10 x 10
Ke = 100000J
Ke = 105J
Ke = mgh
Ke = Pe
\(\frac{1}{2}\)MV2 = mgh
Ke = 1000 x 10 x 10
Ke = 100000J
Ke = 105J