A swimming pool is .1m deep. If it contains water of refractive index 1.3, calculate the apparent depth of pool
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Correct Answer: Option C
Explanation:
n = \(\frac{\text{real depth}}{\text{apparent depth}}\)
1.3 = \(\frac{2.1}{\text{apparent}}\)
A.D = \(\frac{2.1}{1.3} = 1.6\)
n = \(\frac{\text{real depth}}{\text{apparent depth}}\)
1.3 = \(\frac{2.1}{\text{apparent}}\)
A.D = \(\frac{2.1}{1.3} = 1.6\)