A wire of cross-sectional area 0.60mm2 has a restivity of 7.2 x 10-7 \(\Omega\). Calculate the length of wire that will have a resistance of 3\(\Omega\).
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Correct Answer: Option B
Explanation:
R = \(\frac{PL}{A}\)
C = \(\frac{RA}{P}\)
C = \(\frac{0.60 \times 10^{-6} \times 3}{7.2 \times 10^{-7}}\)
C = 2.50m
R = \(\frac{PL}{A}\)
C = \(\frac{RA}{P}\)
C = \(\frac{0.60 \times 10^{-6} \times 3}{7.2 \times 10^{-7}}\)
C = 2.50m