in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]
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Correct Answer: Option C
Explanation:
E - Mec2
E = 1.2 x 10-5 x (3 x 108)2
E = 1.08 x 1012J
E - Mec2
E = 1.2 x 10-5 x (3 x 108)2
E = 1.08 x 1012J