\(^{226}_{88}Ra\) emits two alpha particles to produce polonium(po) nuclide. The correct formula for the nuclide? - SchoolNGR

Search SchoolNGR

\(^{226}_{88}Ra\) emits two alpha particles to produce polonium(po) nuclide. The ...

\(^{226}_{88}Ra\) emits two alpha particles to produce polonium(po) nuclide. The correct formula for the nuclide?

SchoolNGR Classroom

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

A \(^{224}_{86}po\)
B \(^{222}_{86}po\)
C \(^{222}_{84}po\)
D \(^{218}_{84}po\)

Correct Answer: Option D

Explanation:

Prev Current Next

Study Subjects

Stay Updated

Follow us on: