A body is projected at an angle of 30° to the horizontal with a velocity of 150 ms\(^{-1.}\). Calculate the time it takes to reach the greatest height [Take g = 10 ms\(^2\) and neglect air resistance]
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Correct Answer: Option n
Explanation:
Young's Modulus = \(\frac{Fl}{Ae}\)
= \(\frac{1000 \times 2.00}{\frac{1}{3.14 \times 1000} \times \frac{1}{1000} \times \frac{25}{1000}}\)
= 2.55 x 10\(^{10}\)NM\(^{-2}\)
Young's Modulus = \(\frac{Fl}{Ae}\)
= \(\frac{1000 \times 2.00}{\frac{1}{3.14 \times 1000} \times \frac{1}{1000} \times \frac{25}{1000}}\)
= 2.55 x 10\(^{10}\)NM\(^{-2}\)