At a birthday party, the celebrant pops a corked fruit wine. If the cork shoots out of the bottle at an angle of 40o to the horizontal and travels a horizontal distance of 4.50m in 1.25s. Calculate the initial speed of the cork.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
R = Ucos\(\theta\) x t
U = \(\frac{R}{Cos \theta \times t}\)
= \(\frac{4.50}{Cos40N.25}\)
= 4.699m/s
R = Ucos\(\theta\) x t
U = \(\frac{R}{Cos \theta \times t}\)
= \(\frac{4.50}{Cos40N.25}\)
= 4.699m/s