The distance between two successive trough of a wave is 0.4m. If the frequency of the source is 825Hz, Calculate the speed of the wave
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Correct Answer: Option B
Explanation:
v = f\(\lambda\)
= 825 x 0.4
= 330.0ms-1
v = f\(\lambda\)
= 825 x 0.4
= 330.0ms-1