An astronomical telescope has objectives and eye-piece lenses of focal length 3.5m and 5cm respectively. Determine the magnifying power of the telescope when in normal adjustment
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Correct Answer: Option A
Explanation:
Magnify power = \(\frac{f_o}{f_e}\)
= \(\frac{3.5 \times 100}{5.0}\)
= 70
Magnify power = \(\frac{f_o}{f_e}\)
= \(\frac{3.5 \times 100}{5.0}\)
= 70