A man and his friend have masses 70kg and 60kg respectively. If they are seated 1.0m apart, calculate the gravitational force of attraction between them. (G = 6.67 x 10-11 Nm2 kg-2)
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Correct Answer: Option B
Explanation:
F = \(\frac{GM_1M_}{r^2}\)
= \(\6.67 \times 10^{-11} \times 70 \times 60}{1^2}\)
= 2.8014 x 10-7 N
F = \(\frac{GM_1M_}{r^2}\)
= \(\6.67 \times 10^{-11} \times 70 \times 60}{1^2}\)
= 2.8014 x 10-7 N