A projectile is fired with a velocity of 20 ms\(^{-1}\) at an angle of 40° to the horizontal. Determine the components of the velocity of the projectile at its maximum height.
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Correct Answer: Option n
Explanation:
The components of velocity at maximum height are:
Vy = 0
Vx = UCos \(\theta\) = 20 Cos 40°
=15.32ms\(^{-1}\)
The components of velocity at maximum height are:
Vy = 0
Vx = UCos \(\theta\) = 20 Cos 40°
=15.32ms\(^{-1}\)