A body weighing 14N in air is partially immersed in water. If the mass of water displaced in the process is 200g, calculate the upthrust on the body. [g=10\(m/s^{2}\)]
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Correct Answer: Option A
Explanation:
Upthrust = weight of liquid displaced
= mass of liquid displaced \(\times\) acceleration due to gravity
= \(\frac{200}{1000} \times 10\)
= 2N
Upthrust = weight of liquid displaced
= mass of liquid displaced \(\times\) acceleration due to gravity
= \(\frac{200}{1000} \times 10\)
= 2N