The angle at which a projectile must be fired to cover maximum range is
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Correct Answer: Option B
Explanation:
The formula is \(\frac{v^{2}sin2\theta}{g}\)
And the sine graph is highest at 1 with its inverse as 90°. Hence, \(2\theta\) = 90°
\(\theta\) = 45°
The formula is \(\frac{v^{2}sin2\theta}{g}\)
And the sine graph is highest at 1 with its inverse as 90°. Hence, \(2\theta\) = 90°
\(\theta\) = 45°