A solid weighs 10.00N in air, 6N when forcefully immersed in water, and 7.0N when fully immersed in a liquid, X. Calculate the relative density of the liquid X.
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Correct Answer: Option C
Explanation:
R.D = \(\frac{\text {weigh in air - weigh in liquid X}}{\text {weigh in air - weigh in water}}\)
= \(\frac{10 - 7}{10 - 6} = \frac{3}{4}\)
R.D = \(\frac{\text {weigh in air - weigh in liquid X}}{\text {weigh in air - weigh in water}}\)
= \(\frac{10 - 7}{10 - 6} = \frac{3}{4}\)