When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) and E\(_2\) are connected in parallel, combined e.m.f. E is given by

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When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) ...

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A E = E\(_1\) + E\(_2\)E = \(\frac{E_1}{E_2}\)
B \(\frac{1}{E} = \frac{1}{E_1} + \frac{1}{E_2}\)
C E = E\(_1\) = E\(_2\)

Correct Answer: Option A

Explanation:

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When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) ...

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