A current of 2A passes through a wire of resistance 4Ω for 3 minutes. Calculate the energy lost.
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Correct Answer: Option C
Explanation:
Power = current[I]\(^2\) * Resistance[R] → 2\(^2\) * 4 → 4 * 4 = 16watts
time = 3minutes → 3 * 60 = 180s
Energy = power * time → 16 * 180 = 2880j
Power = current[I]\(^2\) * Resistance[R] → 2\(^2\) * 4 → 4 * 4 = 16watts
time = 3minutes → 3 * 60 = 180s
Energy = power * time → 16 * 180 = 2880j