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\(^{226}_{88}Ra\) \(\to\) \(^{222}_{866}Rn\) + X + Energy. The equation above ...

\(^{226}_{88}Ra\) \(\to\) \(^{222}_{866}Rn\) + X + Energy. The equation above represents a nuclear decay of radium isotope. What is X?
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  • A Alpha particle
  • B Beta particle
  • C Gamma ray
  • D Neutron
  • E X – ray
Correct Answer: Option A
Explanation:

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