A cell with an emf of \(1.5 V\) and an internal resistance of \(10 .\). fohims 1 connegted to two resistances of \(2.0\) and \(3.0\) ohms in series. The current produced by this cell is
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Correct Answer: Option A
Explanation:
V=I(R+r)=\frac{1.5}{(5+1)} \quad=\frac{1}{4}
=0.25
V=I(R+r)=\frac{1.5}{(5+1)} \quad=\frac{1}{4}
=0.25