Three \(4-\Omega\) resistors were connected in series by Tola while Ade connected the same set of resistors in parallel. The ratio of the value obtained by Ade to that obtained by Tola is ____________
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Correct Answer: Option B
Explanation:
Tolade
\(R_{T}=3 \times 4 \Omega \quad \frac{1}{R_{T}}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}\)
\(=12 \Omega \quad R_{T}=\frac{4}{3} \Omega\)
Ratio of value obtained
by Ade toTola
$$
=\frac{4}{3}: 12=\frac{4}{3} \times \frac{1}{12}=1: 9
$$
Tolade
\(R_{T}=3 \times 4 \Omega \quad \frac{1}{R_{T}}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}\)
\(=12 \Omega \quad R_{T}=\frac{4}{3} \Omega\)
Ratio of value obtained
by Ade toTola
$$
=\frac{4}{3}: 12=\frac{4}{3} \times \frac{1}{12}=1: 9
$$