The equation
\({ }_{62}^{150} X \rightarrow{ }_{63}^{150} Y+k+\) energy
represents
\({ }_{62}^{150} X \rightarrow{ }_{63}^{150} Y+k+\) energy
represents
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Correct Answer: Option B
Explanation:
\({ }_{62}^{150} X \rightarrow{ }_{63}^{150} Y+{ }_{b}^{a} K+\) energyalancing the nuclear equation, we have \(a=0, b=-1(63\)
\(-62\) ) so that
\(k={ }_{-1}^{0} e-\beta-\) decay
\({ }_{62}^{150} X \rightarrow{ }_{63}^{150} Y+{ }_{b}^{a} K+\) energyalancing the nuclear equation, we have \(a=0, b=-1(63\)
\(-62\) ) so that
\(k={ }_{-1}^{0} e-\beta-\) decay