When sickle cell carrier marries a normal woman, the probability of them having a normal offspring is
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Correct Answer: Option C
Explanation:
A sickle cell carrier (AS) and a normal woman (AA), when crossed will yield:
2 normal offsprings (AA) and 2Â sickle cell carrier (AS).
Hence, the probability of a normal child = \(\frac{2}{4}\)
= \(0.5\)
A sickle cell carrier (AS) and a normal woman (AA), when crossed will yield:
2 normal offsprings (AA) and 2Â sickle cell carrier (AS).
Hence, the probability of a normal child = \(\frac{2}{4}\)
= \(0.5\)