The initial volume of water poured into a bag of dry soil was 50ml and the amount that drained through was 35mI.
The percentage water content of the fully soaked soil is, therefore?
The percentage water content of the fully soaked soil is, therefore?
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Correct Answer: Option D
Explanation:
Percentage of water content (retained) = \(\frac{Water absorbed}{Weight of soil} * 100\)
→ \(\frac{50 - 35}{50} * 100\)
= 30%
Percentage of water content (retained) = \(\frac{Water absorbed}{Weight of soil} * 100\)
→ \(\frac{50 - 35}{50} * 100\)
= 30%