The hydrogen ion concentration of a sample of orange juice is 2.0 X 10\(^{-11}\)moldm\(^{-3}\). What is its p\(^{OH}\)? [log102 = 0.3010]
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Correct Answer: Option C
Explanation:
p\(^{OH}\) = -Log [OH\(^-\)]
 [OH\(^-\) ] = 2.0 X 10\(^{-11}\)moldm\(^{-3}\)
 p\(^{OH}\) = -Log [2.0 X 10\(^{-11}\)]
 p\(^{OH}\) = 10.70
p\(^{OH}\) = -Log [OH\(^-\)]
 [OH\(^-\) ] = 2.0 X 10\(^{-11}\)moldm\(^{-3}\)
 p\(^{OH}\) = -Log [2.0 X 10\(^{-11}\)]
 p\(^{OH}\) = 10.70