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From the graph above, it may be concluded that

From the graph above, it may be concluded that
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
  • A AgNO\(_3\) is probably not soluble at 1100
  • B NaCl is insoluble in water
  • C Pb(NO\(_3\))\(_2\) is more soluble than KCIO\(_3\)
  • D The solubility of KCIO\(_3\) exceeds that of NaCl at all temperature
Correct Answer: Option C
Explanation:
Looking vividly to the graph we can deduce that Pb(NO\(_3\))\(_2\) is more soluble than KCIO\(_3\)

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