A gas occupies 8 dm³ at 200 K. Determine the volume at 600 K.
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Correct Answer: Option D
Explanation:
Applying Charles’ law:<br/>8/200 = Vā/600<br/>Cross multiplying:<br/>200Vā = 4800<br/>Vā = 24 dm³.<br/>The temperature became three times larger, so the volume also became three times larger.
Applying Charles’ law:<br/>8/200 = Vā/600<br/>Cross multiplying:<br/>200Vā = 4800<br/>Vā = 24 dm³.<br/>The temperature became three times larger, so the volume also became three times larger.