What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO2 according to the following equation? C(s) + O2(g) → CO2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm3 at s.t.p]
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Correct Answer: Option B
Explanation:
From the equation, C + O2 → CO2 : 22.dm3 of oxygen is required to form 44g of CO2 the volume of O2 required to produce 4.4gm is x, :. x = 44/44 X 22.4dm3
From the equation, C + O2 → CO2 : 22.dm3 of oxygen is required to form 44g of CO2 the volume of O2 required to produce 4.4gm is x, :. x = 44/44 X 22.4dm3