0 . 1 Faraday of electricity was passed through a solution copper(II) sulphate. The maximumeright of copper deposited on the cathode would be _____________
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Correct Answer: Option D
Explanation:
\(Cu ^{2+}+2 e ^{-}- Cu\)
1mole \(2 F\)
\(2 F\) would deposit Imole of \(Cu\)
iF would deposit \(1 / 2\) mole of \(Cu\)
IF would deposit \((1 / 2 \times 01)\) mole of \(Cu\)
\(=0.05\) mole of copper
mass \(=0.05 \times 63.5\)
\(=3.2 g\)
\(Cu ^{2+}+2 e ^{-}- Cu\)
1mole \(2 F\)
\(2 F\) would deposit Imole of \(Cu\)
iF would deposit \(1 / 2\) mole of \(Cu\)
IF would deposit \((1 / 2 \times 01)\) mole of \(Cu\)
\(=0.05\) mole of copper
mass \(=0.05 \times 63.5\)
\(=3.2 g\)