How many molecules are there in \(5.6 dm 3\) of ammonia at s.t.p.? G.V.M. \(=224\) am 3 at s. \(s\). \(NA =6.02 \times 10^{23} moV\)
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Correct Answer: Option D
Explanation:
t stp \(22.4 dm ^3\) of ammonia have \(6.02 \times 10^{23}\) molecule \(5.6 dm ^3\) of ammonia will have \(\frac{6.02 \cdot 10^{22} \text { molecule } 5.6}{22.4}=1.505 \times 10^{23}\) molecule
t stp \(22.4 dm ^3\) of ammonia have \(6.02 \times 10^{23}\) molecule \(5.6 dm ^3\) of ammonia will have \(\frac{6.02 \cdot 10^{22} \text { molecule } 5.6}{22.4}=1.505 \times 10^{23}\) molecule