\(C _{4} H _{2}+90_{2} \rightarrow 6 CO _{2}+6 H _{2} O\).
The hydrocarbon, \(C _{x} H _{2}\), in the reaction above is most likely ____________
The hydrocarbon, \(C _{x} H _{2}\), in the reaction above is most likely ____________
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Correct Answer: Option C
Explanation:
\(C _{x} H _{y}+9 O _{2} \rightarrow 6 CO _{2}+6 H _{2} O\)
The general form of the equation is
\(C _{x} H _{y}+\left(x+\frac{y}{4}\right) x \rightarrow x CO _{2}+\frac{y}{2} H _{2} O\)y balancing the equation, \(x=6, y / 2=6\), so that the hydrocarbon is \(C _{6} H _{12}\), an alkene \(\left( C _{ n } H _{2 n }\right)\)
\(C _{x} H _{y}+9 O _{2} \rightarrow 6 CO _{2}+6 H _{2} O\)
The general form of the equation is
\(C _{x} H _{y}+\left(x+\frac{y}{4}\right) x \rightarrow x CO _{2}+\frac{y}{2} H _{2} O\)y balancing the equation, \(x=6, y / 2=6\), so that the hydrocarbon is \(C _{6} H _{12}\), an alkene \(\left( C _{ n } H _{2 n }\right)\)