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Sunday, 02 August 2026
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Chemistry Past Questions and Answers

Chemistry Questions

Question 161:
10cm<sup style='font-size: smaller;'>3</sup> of CO is mixed and sparked with 100cm<sup style='font-size: smaller;'>3</sup> of air containing 21% O<sub style='font-size: smaller;'>2</sub>. If all the volumes measured at S.T.P. the volume of resulting gases would be?
  • A 90cm<sup style='font-size: smaller;'>3</sup>
  • B 100cm<sup style='font-size: smaller;'>3</sup>
  • C 105cm<sup style='font-size: smaller;'>3</sup>
  • D 110cm<sup style='font-size: smaller;'>3</sup>
  • E 115cm<sup style='font-size: smaller;'>3</sup>
View Answer & Explanation
Question 162:
A sample of an oxide of mercury weighed 1.00g. When this was heated, oxygen was given off, and 1.00g of mercury metal only was left. What is the formula of the oxide?
  • A Hg<sub style='font-size: smaller;'>2</sub>O
  • B HgO<sub style='font-size: smaller;'>2</sub>
  • C HgO<sub style='font-size: smaller;'>2</sub>
  • D HgO
  • E None of the above
View Answer & Explanation
Question 163:
On heating, under suitable conditions, 1 litres of monoatomic gas,X, combines with 1<sup style='font-size: smaller;'>1</sup>/<sub style='font-size: smaller;'>2</sub> litres of an oxide, What is the formula of the oxide.
  • A XO<sub style='font-size: smaller;'>3</sub>
  • B X<sub style='font-size: smaller;'>2</sub>O<sub style='font-size: smaller;'>3</sub>
  • C X<sub style='font-size: smaller;'>3</sub>O<sub style='font-size: smaller;'>2</sub>
  • D XO<sub style='font-size: smaller;'>2</sub>
  • E None of the above
View Answer & Explanation
Question 164:
If 1 litre of 2.2M sulphuric acid is poured into a bucket containing 10 litre of water,and resulting solution mixed thoroughly, the resulting sulpuric acid concentration will be?
  • A 2.2 M
  • B 1.1 M
  • C O.22 M
  • D 0. 11 M
  • E 0.20 M
View Answer & Explanation
Question 165:
Which of the following reactions is correct as as written?
  • A FeCl<sub style='font-size: smaller;'>2</sub> + 3NH<sub style='font-size: smaller;'>4</sub>OH → Fe(OH)<sub style='font-size: smaller;'>3</sub> + 3NH<sub style='font-size: smaller;'>4</sub>Cl
  • B Pb<sub style='font-size: smaller;'>2</sub>O<sub style='font-size: smaller;'>3</sub> + 4HCl → PbCl<sub style='font-size: smaller;'>2</sub> + 2H<sub style='font-size: smaller;'>2</sub>O
  • C PbNO<sub style='font-size: smaller;'>3</sub> + H<sub style='font-size: smaller;'>2</sub>S → PbS + 2HNO<sub style='font-size: smaller;'>3</sub>
  • D NaOH + H<sub style='font-size: smaller;'>2</sub>SO<sub style='font-size: smaller;'>4</sub> → NaHSO<sub style='font-size: smaller;'>4</sub> +H<sub style='font-size: smaller;'>2</sub>O
  • E 2NH<sub style='font-size: smaller;'>4</sub>NO<sub style='font-size: smaller;'>3</sub> → N<sub style='font-size: smaller;'>2</sub> + 2H<sub style='font-size: smaller;'>2</sub>O
View Answer & Explanation