Find correct to the nearest degree,5 the angle between p = 12i - 5j and q = 4i +3j
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Correct Answer: Option A
Explanation:
Cos \(\theta\) = \(\frac{4(12) + (-5)(3)}{\sqrt{12^2 + (-5)^2}\sqrt{4^2 + 3^2}}\)
Cos\(\theta\) = \(\frac{48 - 15}{(\sqrt{189})(\sqrt{25})}\)
\(\theta = cos^{-1}\) (\(\frac{33}{61.28}\))
\(\theta\) = cos\(^{-1}\)0.5367
\(\theta\) = 59\(^o\)
Cos \(\theta\) = \(\frac{4(12) + (-5)(3)}{\sqrt{12^2 + (-5)^2}\sqrt{4^2 + 3^2}}\)
Cos\(\theta\) = \(\frac{48 - 15}{(\sqrt{189})(\sqrt{25})}\)
\(\theta = cos^{-1}\) (\(\frac{33}{61.28}\))
\(\theta\) = cos\(^{-1}\)0.5367
\(\theta\) = 59\(^o\)