Find the area between line y = x + 1 and the x-axis from x = -2 to x = 0.
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Correct Answer: Option C
Explanation:
\(\int^0_{-2} x + 1\) x\(^2 + x|^0_{-2}\)
0 - (2\(^2 - 2\))
= 2 square units
\(\int^0_{-2} x + 1\) x\(^2 + x|^0_{-2}\)
0 - (2\(^2 - 2\))
= 2 square units