Jamb Mathematics Questions
Question 6:
Arrange \(\frac{3}{5}\),\(\frac{9}{16}\), \(\frac{34}{59}\) and \(\frac{71}{97}\) in ascending order of magnitude.
- A \(\frac{3}{5}\), \(\frac{9}{16}\), \(\frac{34}{59}\), \(\frac{71}{97}\)
- B \(\frac{9}{16}\), \(\frac{34}{59}\), \(\frac{3}{5}\) , \(\frac{71}{97}\)
- C \(\frac{3}{5}\), \(\frac{9}{16}\), \(\frac{71}{97}\), \(\frac{34}{59}\)
- D \(\frac{9}{16}\), \(\frac{3}{5}\), \(\frac{71}{97}\), \(\frac{34}{59}\)
Question 7:
The sum of the progression is 1 + x + x2 + x3 + ......
- A \(\frac{1}{1 - x}\)
- B \(\frac{1}{1 + x}\)
- C \(\frac{1}{x - 1}\)
- D \(\frac{1}{x}\)
Question 8:
The number of telephone calls N between two cities A and B varies directly as the population P\(_{A}\), P\(_B\) respectively and inversely as the square of the distance D between A and B. Which of the following equations represents this relation?
- A N = \(\frac{kp_A}{D^2} + {cp_B}{D^2}\)
- B N = \(\frac{k P_{A} P_{B} }{D^2}\)
- C N = \(\frac{kD_AP_D}{B^2}\)
- D N = \(\frac{kD^2_AP_D}{B}\)
Question 9:
Find the square root of 170 - 20\(\sqrt{30}\)
- A 2 \(\sqrt{10}\) - 5\(\sqrt{3}\)
- B 2 \(\sqrt{5}\) - 5\(\sqrt{6}\)
- C 5 \(\sqrt{10}\) - 2\(\sqrt{3}\)
- D 3 \(\sqrt{5}\) - 8\(\sqrt{6}\)