Jamb Mathematics Questions
Question 6:
The factors of 6x - 5 - x2 are
- A -(x + 3)(x + 2)
- B (x + 5)(x + 1)
- C (x - 5)(1 - x)
- D (x + 1)(x + 5)
Question 7:
The solution of the quadratic equation bx2 + cx + a = 0 is given by
- A X = b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)
- B X = c \(\pm\) \(\frac{\sqrt{b^2 - 4ab}}{2b}\)
- C X = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)
- D X = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2b}\)
Question 8:
The graphical method of solving the equation x3 + 3x2 + 4x - 28 = 0 is by drawing the graphs of the curves
- A Y = x3 and y = 3x2 + x - 28
- B Y = x3 + 3x2 + 4x + 4 and the line y = \(\frac{28}{x}\)
- C Y = x3 + 3x2 + 4x and y
- D Y = x2 + 3x + 4 and y = \(\frac{28}{x}\)
- E Y = x2 + 3x + 4 and line y = 28x
Question 9:
Write the equation 2 log2x - x log2(1 + y) = 3 in a form not involving logarithms
- A 2x(1 + y) = 3
- B 2x - x(1 + y) = 8
- C X2 = 8(1 + y)x
- D X2 - x(1 + y) = 8
- E X2 - (1 + y)2 = 8
Question 10:
Find \(\alpha\) and \(\beta\) such that x\(\frac{3}{8}\) x y\(\frac{-6}{7}\) x (\(\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}\))\(\frac{1}{9}\) = \(\frac{y^{\alpha}}{y^{\beta}}\)
- A \(\alpha\) = 1, \(\beta\) = \(\frac{5}{7}\)
- B \(\alpha\)= 1, \(\beta\) = -\(\frac{5}{7}\)
- C \(\alpha\)= \(\frac{3}{5}\), \(\beta\) = -6
- D \(\alpha\)= 1, \(\beta\) = -\(\frac{3}{5}\)