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Friday, 06 November 2026
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Mathematics Past Questions and Answers

Jamb 1983 Mathematics Questions

Question 31:
In a sample survey of a University Community, the following table shows the percentage distribution of the number of members per house hold
\(\begin{array}{c|c} \text{No. of members per household} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & \text{Total} \\ \hline \text{No. of households} & 3 & 12 & 15 & 28 & 21 & 10 & 7 & 4 & 100\end{array}\)
What is the median?
  • A 4
  • B 3
  • C 5
  • D 4.5
  • E None
View Answer & Explanation
Question 32:
On a square paper of length 2.524375cm is inscribed square diagram of length 0.524375cm. Find the area of the paper not covered by the diagram. correct to 3 significant figures.
  • A 6.00cm<sup style='font-size: smaller;'>2</sup>
  • B 6.10cm<sup style='font-size: smaller;'>2</sup>
  • C 6cmv
  • D 6.09cm<sup style='font-size: smaller;'>2</sup>
  • E 4.00cm<sup style='font-size: smaller;'>2</sup>
View Answer & Explanation
Question 33:
Simplify \(\sqrt[3]{\frac{27a^{-9}}{8}}\).
  • A \(\frac{9a^2}{2a^3}\)
  • B \(\frac{3}{2a^3}\)
  • C \(\frac{2}{3a^2}\)
  • D \(\frac{3a^2}{2}\)
View Answer & Explanation
Question 34:
PQR is the diagram of a semicircle RSP with centre at Q and radius of length 3.5cm. If QPT = 60o. Find the perimeter of the figure PTRS. \(\pi\) = \(\frac{22}{7}\)
  • A 25cm
  • B 18cm
  • C 36cm
  • D 29cm
  • E 25.5cm
View Answer & Explanation
Question 35:
In a triangle PQT, QR = \(\sqrt{3}cm\), PR = 3cm, PQ = \(2\sqrt{3}\)cm and PQR = 30o. Find angles P and R
  • A P = 60<sup style='font-size: smaller;'>o</sup> and R = 90<sup style='font-size: smaller;'>o</sup>
  • B P = 30<sup style='font-size: smaller;'>o</sup> and R = 120<sup style='font-size: smaller;'>o</sup>
  • C P = 90<sup style='font-size: smaller;'>o</sup> and R = 60<sup style='font-size: smaller;'>o</sup>
  • D P = 60<sup style='font-size: smaller;'>o</sup> and R 60<sup style='font-size: smaller;'>o</sup>
  • E P = 45<sup style='font-size: smaller;'>o</sup> and R = 105<sup style='font-size: smaller;'>o</sup>
View Answer & Explanation