Peter is 15 years older than Kenneth. If 5 years ago, Peter was 3 times as old as Kenneth, then find Peter's present age?
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Correct Answer: Option B
Explanation:
Let Kenneth's percentage age \(= K\). and Peter's present age \(= P\)
\begin{aligned}
& P = K +15 \ldots \ldots(1) \\
&( P -5)=3( K -5)
\end{aligned}
\begin{aligned}
& P -5=3 K -15 \\
& P -3 K =-15+5 \\
& P -3 K =-10 \\
&-2 K =-10-15 \\
&-2 K =-25 \\
& K =\frac{-25}{-2}=12.5
\end{aligned}
Put K \(12.5+15=27.5\) yrs
Let Kenneth's percentage age \(= K\). and Peter's present age \(= P\)
\begin{aligned}
& P = K +15 \ldots \ldots(1) \\
&( P -5)=3( K -5)
\end{aligned}
\begin{aligned}
& P -5=3 K -15 \\
& P -3 K =-15+5 \\
& P -3 K =-10 \\
&-2 K =-10-15 \\
&-2 K =-25 \\
& K =\frac{-25}{-2}=12.5
\end{aligned}
Put K \(12.5+15=27.5\) yrs