To a certain number 7 is added to the sum is multiplied by five and the product is divided by nine, then three is subtracted from the quotient, and the remainder left is twelve?
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Correct Answer: Option B
Explanation:
Let the number be \(x\)
\begin{aligned}
&\frac{(x+7) \times 5}{9}-3=12 \\
&\frac{5(x+7)}{9}=12+3 \\
&\frac{5(x+7)}{9}=15
\end{aligned}ivide through by 5
\begin{aligned}
&\frac{(x+7)}{9}=3 \\
&x+7=3 \times 9 \\
&x+4=27 \\
&x=27-7=20
\end{aligned}
Let the number be \(x\)
\begin{aligned}
&\frac{(x+7) \times 5}{9}-3=12 \\
&\frac{5(x+7)}{9}=12+3 \\
&\frac{5(x+7)}{9}=15
\end{aligned}ivide through by 5
\begin{aligned}
&\frac{(x+7)}{9}=3 \\
&x+7=3 \times 9 \\
&x+4=27 \\
&x=27-7=20
\end{aligned}