If \(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = 1, solve for x.
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Correct Answer: Option C
Explanation:
\(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = 1
\(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = \(\log_{10}\)10
\(\log_{10}\)\(\frac{6x - 4}{2}\) - \(\log_{10}\)10
\(\frac{6x - 4}{2}\) = 10
6x - 4 = 2 x 10
= 20
6x = 20 + 4
6x = 20
x = \(\frac{24}{6}\)
x = 4
\(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = 1
\(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = \(\log_{10}\)10
\(\log_{10}\)\(\frac{6x - 4}{2}\) - \(\log_{10}\)10
\(\frac{6x - 4}{2}\) = 10
6x - 4 = 2 x 10
= 20
6x = 20 + 4
6x = 20
x = \(\frac{24}{6}\)
x = 4