If F = \(\frac{9}{5}\)C + 32, find C when F = 98.6
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
F = \(\frac{9}{5}\)C + 32
When F = 98.6
98.6 = \(\frac{9}{5}\)C + 32
98.6 - 32 = \(\frac{9}{5}\)C
66.6= \(\frac{9}{5}\)C
66.6 x 5 = 9C
C = \(\frac{66.6 \times 5}{9}\)
= 37
F = \(\frac{9}{5}\)C + 32
When F = 98.6
98.6 = \(\frac{9}{5}\)C + 32
98.6 - 32 = \(\frac{9}{5}\)C
66.6= \(\frac{9}{5}\)C
66.6 x 5 = 9C
C = \(\frac{66.6 \times 5}{9}\)
= 37